WHAT YOU’LL BE ABLE TO DO
Find the network, broadcast address, and ordinary host range for a /26 subnet.
Read the prefix
In 192.168.10.70/26, the prefix reserves 26 of the 32 bits for the network. Six host bits remain, giving 64 addresses per block.
32 − 26 = 6 → 2⁶ = 64 addresses
Find the block
Within this /24, the /26 blocks start at .0, .64, .128, and .192. The address .70 sits in the block that starts at .64.
192.168.10.64 through 192.168.10.127
Name the boundaries
For this ordinary /26 subnet, .64 identifies the network and .127 is the broadcast address. Assignable host addresses run from .65 through .126. Special cases such as /31 and /32 need different reasoning.
Network .64 · hosts .65–.126 · broadcast .127
Further reading: CIDR (RFC 4632)
Check your reasoning.
Which /26 network contains 192.168.10.130?
Before you move on
Use these prompts to decide what to revisit.
0 of 3 reflection prompts checked
FROM EXPLANATION TO EXPLORATION
Now change something.
Try .70 with /26, then /27. Predict the boundaries before checking.
Open the subnet explorer